D.E.V.

Unit 1 - Measurement

Find the exact value of each trigonomic function.

The first step is to get csc θ by itself:

-8 –8csc θ = -24

Add 8 to both sides of the equal sign

-8csc θ = -16

Divide both sides by -8

 csc θ = 2

Change to sine

1/sin θ =2

Move sine to numerator

sin θ = ½

Look on unit circle to see where sin is ½

Θ = π/6 , 5π/6

Unit 2 – Graphing

To describe a transformation, you will first need to understand the different variables of a graph and what they do.

The formula:

          y = a * cosb ( θ – h) +k

a = rate/amplitude                                      h = horizontal shift

b = horizontal stretch/shrink             k = vertical shift

When given the problem:     y = 4sin (θ - 3π/2) + 6

The 4 is your “a” value, therefore, the amplitude is 4.

There is a right shift of 3π/4

The graph shifts up 6

All of this can be determined from looking at the equation and matching up the variables.

Unit 3 – Identities

Problem: cosθ/secθ + sinθ/cscθ

First, convert everything into sine and cosine.

= cosθ/(1/cosθ) + sinθ/ (1/sinθ)

= cos²θ + sin²θ

= 1

The answer 1 can be found from looking at the Pythagorean Identities.

Unit 4 – Inverses

Problem: sin(cos^-1  (√3)/2)

First, find the cosine, and use that to fine the sine.

= sin(π/6)

Then, look for the sin of π/6 on the Unit Circle.

Answer: ½

I chose to do a problem from each unit because this way, everything is covered for my personal review. I really wanted to focus on the basics because I have been struggling in this class. I feel like going through the basics has actually helped me a lot more in understanding where I have made so many mistakes. Overall, I was able to understand what was going on and the project was very eye opening. When working on it by yourself, you really get a chance to see where you struggle and need to work harder at. I saw this as a very beneficial way to review because you were able to tackle what you needed to. I’m hoping that I will do a lot better on the exam than I have been on quizzes and tests.